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This problem was asked by Google. Given the root to a binary tree, implement serialize(root), which serializes the tree into a string, and deserialize(s), which deserializes the string back into the tree. For example, given the following Node class ``` class Node: def __init__(self, val, left=None, right=None): self.val = val self.left = left self.right = right ``` The following test should pass: ``` node = Node('root', Node('left', Node('left.left')), Node('right')) assert deserialize(serialize(node)).left.left.val == 'left.left' ```
/* I fail this question for sure. I just looked up what a binary tree is.*/
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