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  <div class="container">

  <textarea id="language_input" type="text"/>
3 22 +</textarea>
  <div class="results" id="language_output">5</div>

  <div id="stack_output"></div>

  <h4>A Simple Stack Based Language</h4>
  <p>Simple Stack based language in postfix notation.</p>

  <p>Ehem,  I'll say that again in English</p>

  <h4>A Backwards Calculator</h4>
  <p> a really simple calculator with a twist.</p>

  <p>My goal is to get to an easy place to experiment with various ways of visualizing the stack</p>

  <p>Postfix means instead of writing "2 + 3" you write "3 2 +". Make sure there is space between every number and every operator. Parentheses will not help you here.</p>


3 22 +        ->        25


  <h5>How it works</h5>

  <p> It's kind of hard to explain. That's what I meant when I said I want to visualize this. I don't know exactly what it will look like when I'm satisfied, but I hope it helps someone understand this type of language (because it's really cool).</p>

              .container {
  float: left;
  margin: 0 60px 0 60px;

.details {

var selInput = d3.select('#language_input')
  .on('keyup', _.debounce(executeFromInput, 500))
var selOutput = d3.select('#language_output')

// Drive first one

function executeFromInput() {
  var input = selInput.node().value;
  var tokens = parse(input)
  var output = execute(tokens);

function execute(tokens) {
  var stack = [];
  _.each(tokens, function (t, i) {
    if (stack.length > 10000) return userError('Stack overflow. That means something went horribly wrong on my end. Sorry boo.');
    switch (t.type) {
    // For values, just throw'm on to the stack.
    case "number":
    // Operators
    case "operator":
     if (stack.length < 2) return userError('Stack underflow. That means you used an operator with not enough values on the stack.');

     // Take operatands off of stack.
     var a = stack.pop();
     var b = stack.pop();

     // Operator implementations
     switch(t.value) {
     case '+':
       log(a, b, t)
       a.value = a.value + b.value;
     case '-':
       a.value = a.value - b.value;
     case '*':
       a.value = a.value * b.value;
     case '/':
       a.value = a.value / b.value;

     // Finally push new value back on stack;
  return stack.map(function (t, i) { return t.value }).join(' ')

function parse(input) {
  var tokens = [];
  // Tokens are any-whitespace delimited
  // TODO: Can reduce this by using regex that matches any group of whitespace for split, instead of string
  _.each(input.split(' '), function (word, i) {
    // First match group is operators, second match group is values. Reserving a lot more than I'm implementing. See execute()
    var reTokens= /(\+|\-|\/|\*|\x|\^)|(\d+(.\d*)?(e\d*)?)/i;
    var matchTokens = word.match(reTokens);
    // Do nothing with words we don't understand
    if ( ! matchTokens ) return;
    var token = {
      type: 'BLANK_TOKEN_TYPE',
      value: 'BLANK_TOKEN_VALUE',
    var op = matchTokens[1];
    var number = matchTokens[2];
    if (op) {
      token.type = 'operator';
      token.value = op
    } else if (number) {
      token.type = 'number';
      token.value = parseFloat(number, 10)
  return tokens;
function userError(message) {
    throw new Error(message)

function log(mess,ag,es) { console.log.apply(console, arguments) }

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